Open System – 1^{st} Low

T = 366 K P_{initial} = 1 bar

P = 2 bar T_{initial} = 311 K

Gas (air): C_{p} = 29.3 J/mol K

Non-steady State analysis:

The 1^{st} Law reduces to:

or

Integration from a® b & c® d:

Dividing equation **A**
by **B** yields:

Now we can express:

For this reversible process: **C**
may be written:

or