Open System – 1^st Low

T = 366 K P_initial = 1 bar

P = 2 bar T_initial = 311 K

Gas (air): C_p = 29.3 J/mol K

Non-steady State analysis:

The 1^st Law reduces to:

or

Integration from a® b & c® d:

Dividing equation A by B yields:

Now we can express:

For this reversible process: C may be written:

or